记 S n 为等差数列 { a n } 的前 n项和.已知 S 4 = 0 , a 5 = 5 ,则( )
a n = 2 n - 5
a n = 3 n - 10
S n = 2 n 2 - 8 n
S n = 1 2 n 2 - 2 n
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