(1)计算: | 1 - 3 | + 3 tan 30 ∘ - ( 3 - 5 ) 0 - - 1 3 - 1 .
(2)解不等式组 2 x + 1 > 0 ① 2 - x 2 ≥ x + 3 3 ② .
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