如图1,在正方形ABCD中,AE平分∠CAB,交BC于点E,过点C作CF⊥AE,交AE的延长线于点G,交AB的延长线于点F.
(1)求证:BE=BF;
(2)如图2,连接BG、BD,求证:BG平分∠DBF;
(3)如图3,连接DG交AC于点M,求AEDM的值.
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